编写一个C#控制台应用程序，从键盘输入年份，判断此年份是不是闰年。
2024-05-14
1. 编写一个C#控制台应用程序，从键盘输入年份，判断此年份是不是闰年。
1、打开编译软件visual studio2010，找到起始界面的菜单栏，选择“文件”->“新建”->“项目”。
2、在新建项目页面中，选择创建一个C#的控制台程序，具体创建如下图的红框框中部分。给项目命名为“IsRunNian”。
3、用Console.Write方法输入提示信息，Console.Write("请输入你要判断的年份：");
将输入的信息存储到strnian这个字符串中，stringstrnian=Console.ReadLine();
4、将输入的信息转化成整数，并判断输入的数是不是在大于等于0的正整数，如果不是则提示“输入的信息不符合要求”。
可以看到，输入-2121弹出输入信息不符合要求。
5、判断输入的年是否是闰年，能被4整除但是不能被100整除的是闰年；
能被400整除的是闰年。具体实现代码如下图，红框框中的就是闰年实现的代码。
6、编译运行程序，可以来输入自己不同年份来检测程序功能。当输入2000年的时候提示是闰年。
7、程序功能检测，输入2200，提示不是闰年。这和实际情况符合，功能完美实现。
2. 用C＃写程序”输入年月确定后显示这个月有几天（注意润年和平年）”
具体的验证输入信息对不对我可就不加了 比如输入信息合法性什么的
希望这个对你有帮助 主要DateTime没有DayOfWeek 和DayOfYear
主要的还是告诉你 不论你写什么 一定要模块化
using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace DayOfMonth
{
class Program
{
// http://zhidao.baidu.com/question/81922821.html?fr=id_push
// 用C＃写程序”输入年月确定后显示这个月有几天（注意润年和平年）”
// 100整除并且不能被400整除的年数不是闰年，除此之外只要能被4和400整除的就是闰年
static void Main(string[] args)
{
string example = "This app will return Days of Month want you want, please give some info (includes Year and Month) such as below:\
Please input Year :\
2008\
Please input Month :\
1\
Days of 2008.1 is 31";
string noticeYear = "Please input Year :";
string noticeMonth = "Please input Month :";
string expectedYear = string.Empty;
string expectedMonth = string.Empty;
uint daysOfMonth = uint.MinValue;
Console.WriteLine("{0}", example);
Console.WriteLine("{0}", noticeYear);
expectedYear = Console.ReadLine();
Console.WriteLine("{0}", noticeMonth);
expectedMonth = Console.ReadLine();
daysOfMonth = GetDaysOfMonth(GetTypeOfMoMonth(expectedMonth), GetTypeOfYear(expectedYear));
Console.WriteLine("Days of {0} in {1} is {2}", expectedMonth, expectedYear, daysOfMonth.ToString());
Console.ReadLine();
}
public enum DayInMonth : uint
{
January = 31,
February = 28,
FebruaryLeapYear = 29,
March = 31,
April = 30,
May = 31,
June30,
July = 31,
August = 31,
September = 30,
October = 31,
November = 30,
December = 31
}
public enum TypeOfYear : uint
{
LeapYear,
NonLeapYear
}
public static uint GetDaysOfMonth(DayInMonth month, TypeOfYear year)
{
uint daysOfMonth = uint.MinValue;
daysOfMonth = Convert.ToUInt32(month);
if (year.Equals(TypeOfYear.LeapYear) && month.Equals(DayInMonth.February))
{
daysOfMonth = Convert.ToUInt32(DayInMonth.FebruaryLeapYear);
}
return daysOfMonth;
}
public static TypeOfYear GetTypeOfYear(string expectedYear)
{
TypeOfYear typeOfYear = TypeOfYear.NonLeapYear;
int formatYear = int.MinValue;
formatYear = Convert.ToInt32(expectedYear);
if ((0 == (formatYear % 4)) && (0 == (formatYear % 400)))
{
typeOfYear = TypeOfYear.LeapYear;
}
return typeOfYear;
}
public static DayInMonth GetTypeOfMoMonth(string expectedMonth)
{
DayInMonth typeOfMonth = DayInMonth.January;
int formatMonth = int.MinValue;
formatMonth = Convert.ToInt32(expectedMonth);
switch (formatMonth)
{
case 1:
case 3:
case 5:
case 7:
case 8:
case 10:
case 12:
typeOfMonth = DayInMonth.January;
break;
case 4:
case 6:
case 9:
case 11:
typeOfMonth = DayInMonth.April;
break;
case 2:
typeOfMonth = DayInMonth.February;
break;
default:
Console.WriteLine("Error type of Month, no matched item");
break;
}
return typeOfMonth;
}
}
}
3. C#中 如何表示昨天
==========
//获取昨天的日期，只要用今天的日期-1就可以了
DateTime.Now是获取今天时间
下面重载了时间的-方法只要调用Date.operater -就可以获得昨天日期了
#include
using namespace std;
int day_tab[2][12]={{31,28,31,30,31,30,31,31,30,31,30,31},{31,29,31,30,31,30,31,31,30,31,30,31}};
class Date
{
int year,month,day;
bool leap(int);
int dton(Date &);
Date ntod(int);
public:
Date() {} //默认构造函数;
Date(int y,int m,int d) {year=y;month=m;day=d;}//重载构造函数;
Date(const Date &d) //复制构造函数;
{
year=d.year;
month=d.month;
day=d.day;
}
Date operator+(int days) //返回一日期加上天数得到的日期;
{
static Date date;
int number=dton(*this)+days;
date=ntod(number);
return date;
}
Date operator-(int days) //返回一日期减去天数得到的日期;
{
static Date date;
int number=dton(*this)-days;
date=ntod(number);
return date;
}
int operator-(Date &b) //返回两日期相差的天数;
{
int days=dton(*this)-dton(b)-1;
return days;
}
bool operator < (const Date d)
{
if((year<d.year) || (year==d.year && month<d.month) || (year==d.year && month==d.month && day<d.day))
return true;
else
return false;
}
bool operator == (const Date d)
{
if((year==d.year && month==d.month && day==d.day))
return true;
else
return false;
}
bool operator > (const Date d)
{
if((year>d.year) || (year==d.year && month>d.month) ||(year==d.year && month==d.month && day>d.day))
return true;
else
return false;
}
void getDate()
{
cout<<"请输入日期:"<<endl;
cout<<"年份:";
cin>>year;
cout<<"月份:";
cin>>month;
cout<<"日期:";
cin>>day;
}
void display() {cout<<year<<"."<<month<<"."<<day<<endl;}
};
bool Date::leap(int year) //判断指定的年份日否为闰年;
{
if(year%4==0 && year%100!=0 || year%400==0)
return true;
else
return false;
}
int Date::dton(Date &d) //将指定的日期转换成从0年0月0日起的天数;
{
int y,m,days=0;
for(y=1;y<=d.year;y++)
if(leap(y)) days+=366;
else days+=365;
for(m=0;m<d.month-1;m++)
if(leap(d.year)) days+=day_tab[1][m];
else days+=day_tab[0][m];
days+=d.day;
return days;
}
Date Date::ntod(int n) //将指定的0年0月0日起的天数转换成对应的日期;
{
int y=1,m=1,d,rest=n,lp;
while(1)
{
if(leap(y))
{
if(rest<=366) break;
else rest-=366;
}
else
{
if(rest<=365) break;
else rest-=365;
}
y++;
}
y--;
lp=leap(y);
while(true)
{
if(lp)
{
if(rest>day_tab[1][m-1]) rest-=day_tab[1][m-1];
else break;
}
else
{
if(rest>day_tab[0][m-1]) rest-=day_tab[0][m-1];
else break;
}
m++;
}
d=rest;
return Date(y,m,d);
}
void main()
{
Date now;
now.getDate();
cout<<"now:";now.display();
Date d1=now+1,d2=now-1;
cout<<"now+1:";d1.display();
cout<<"now-1:";d2.display();
}
以上是自己实现的方法
系统方法是：
DateTime.Now.Date.AddDays(-1)
4. C#winform 如何将一个长的Point[]数组分割成多个Point 数组
final int LEAPYEAR = 366; int[] YEAR = new int[LEAPYEAR]; 和 int[] YEAR = new int[366];
5. 用C#控制台应用程序对NextDate问题运用决策表法设计测试用例
1. 输入是否合法
day_list[12] = {31,28,31,30,31,30,31,31,30,31,30,31};
// 判断条件：
( year>=1920 && year<=2050 ) &&
(
( month>=1 && month=1 && day<=day_list[month-1] )||
( month==2 && isLeap(year) && day>=1 && day<=29 )
)
2.
/*
函数说明： int NextDate(int month,int day,int year)
如果还有明天，返回1；
如果输入不合法，返回-1；
如果超出处理范围，返回-2
*/
int bLeapYear;
int newY,newM,newD;
newY = year;
newM = month;
newD = day;
bLeapYear = ( (year%4)==0 && (year%100)!=0 ) || (year%400)==0;
if ( year>=1920 && year<=2050 )
{
if ( month>=1 && month=1 )
{
if ( day<day_list[month-1] )
{
newD += 1;
}
else if ( day==day_list[month-1] && !bLeapYear )
{
if ( month==12 && day==31 )
{
if ( year==2050 ) return -2;
else
{
newY += 1; newM = 1; newD = 1;
}
}
else
{
newM += 1; newD = 1;
}
}
else if ( month==2 && bLeapYear )
{
if ( day==28 ) newD = 29;
else if( day==29 )
{ newM = 3; newD = 1; }
else return -1;
} else return -1;
}
}
// 输出
return 1;
3. 测试方法：
3.1 闰年二月的最后一天
3.2 闰年二月的第28天
3.3 非闰年二月的第28天
3.4 每年的非二月的月末
3.5 每年的十二月的月末
3.6 2050年十二月的月末
3.7
year>2050 || year12 || day<1 ||
(day>day_list[month-1] && month>=1 && month<=12 && month!=2 ) ||
(day>28 && month==2 && !bLeapYear ) ||
(day>29 && month==2 && bLeapYear )
3.8 闰年非二月的月末 （3.4的分支）
测试出程序错误：
4.1
else if ( day==day_list[month-1] && !bLeapYear )
应改为：
else if ( day==day_list[month-1] && month!=2 )
4.2
else if ( month==2 && bLeapYear )
{
if ( day==28 ) newD = 29;
else if( day==29 )
{ newM = 3; newD = 1; }
else return -1;
}
应改为：
else if ( month==2 )
{
if ( day==28 && bLeapYear ) newD = 29;
else if( day==28 && !bLeapYear || ( day==29 && bLeapYear ) )
{ newM = 3; newD = 1; }
else return -1;
}
6. c#中true的问题
bool result;
if (year % 400 == 0 || year % 4 == 0 && year % 100 != 0)
{
result = true;
}
else
result = false;
if (result)
{
Console.WriteLine("闰年");
}
else
{
Console.WriteLine("不是闰年");
}
这样能看懂吧
7. C# 中 怎样获得当前星期以及农历时间
这是网上的例子，你仔细看看
using System;
using System.Data;
using System.Configuration;
using System.Web;
using System.Web.Security;
using System.Web.UI;
using System.Web.UI.WebControls;
using System.Web.UI.WebControls.WebParts;
using System.Web.UI.HtmlControls;
using System;
using System.Collections.Generic;
using System.Text;
using System.Globalization;
///
/// chinaDate 的摘要说明
///
public class chinaDate
{
public string cDate()
{
ChineseLunisolarCalendar l = new ChineseLunisolarCalendar();
DateTime dt = DateTime.Today; //转换当日的日期
//dt = new DateTime(2006, 1,29);//农历2006年大年初一（测试用），也可指定日期转换
string[] aMonth ={"","正月", "二月", "三月", "四月", "五月", "六月", "七月", "八月", "九月", "十月", "十一月", "腊月", "腊月" };
//a10表示日期的十位!
string[] a10 ={ "初", "十", "廿", "卅" };
string[] aDigi ={ "O", "一", "二", "三", "四", "五", "六", "七", "八", "九" };
string sYear = "", sYearArab = "", sMonth = "", sDay = "", sDay10 = "", sDay1 = "", sLuniSolarDate = "";
int iYear, iMonth, iDay;
iYear = l.GetYear(dt);
iMonth = l.GetMonth(dt);
iDay = l.GetDayOfMonth(dt);
//Format Year
sYearArab = iYear.ToString();
for (int i = 0; i < sYearArab.Length; i++)
{
sYear += aDigi[Convert.ToInt16(sYearArab.Substring(i, 1))];
}
//Format Month
int iLeapMonth = l.GetLeapMonth(iYear); //获取闰月
if (iLeapMonth > 0 && iMonth<=iLeapMonth)
{
//for (int i = iLeapMonth + 1; i < 13; i++) aMonth[i] = aMonth[i - 1];
aMonth[iLeapMonth] = "闰" + aMonth[iLeapMonth-1];
sMonth = aMonth[l.GetMonth(dt)];
}
else if (iLeapMonth > 0 && iMonth > iLeapMonth)
{
sMonth = aMonth[l.GetMonth(dt) - 1];
}
else
{
sMonth = aMonth[l.GetMonth(dt)];
}
//Format Day
sDay10 = a10[iDay / 10];
sDay1 = aDigi[(iDay % 10)];
sDay = sDay10 + sDay1;
if (iDay == 10) sDay = "初十";
if (iDay == 20) sDay = "二十";
if (iDay == 30) sDay = "三十";
//Format Lunar Date
//sLuniSolarDate = dt.Year+"年"+dt.Month+"月"+dt.Day+"日 "+Weeks(dt.DayOfWeek.ToString())+" 农历" + sYear + "年" + sMonth + sDay;
sLuniSolarDate =" 农历" + sMonth + sDay;
return sLuniSolarDate;
}
private string Weeks(string Weeken)
{
switch (Weeken)
{
case "Monday":
return "星期一";
break;
case "Tuesday":
return "星期二";
break;
case "Wednesday":
return "星期三";
break;
case "Thursday":
return "星期四";
break;
case "Friday":
return "星期五";
break;
case "Saturday":
return "星期六";
break;
case "Sunday":
return "星期日";
break;
default:
return " ";
}
}
}
二、第二步
chinaDate s = new chinaDate();
Label1.Text = DateTime.Now.ToShortDateString() + " " + CaculateWeekDay(DateTime.Now.DayOfWeek.ToString()) + " " + s.cDate();
三、第三步
#region 得到今天是星期几
protected string CaculateWeekDay(string week)
{
string weekstr = "";
switch (week)
{
case "Monday": weekstr = "星期一"; break;
case "Tuesday": weekstr = "星期二"; break;
case "Wednesday": weekstr = "星期三"; break;
case "Thursday": weekstr = "星期四"; break;
case "Friday": weekstr = "星期五"; break;
case "Saturday": weekstr = "星期六"; break;
case "Sunday": weekstr = "星期日"; break;
}
return weekstr;
}
#endregion
8. C#获取服务器时间??急急急请高手帮忙..
唉,花了点时间,现做了一个,你把下面的代码保存为ASPX就可以运行了,我已经测试通过.
下面这个Hidden变量用来暂存服务器时间
">
getServerTime();
//计算当前服务器时间
function getServerTime()
{
//取得要进行显示的日期
var datetimeYou = document.getElementById('ServerTime').value.split(" ");
var yout1 = datetimeYou[0].split("-");
var yout2 = datetimeYou[1].split(":");
var nowY = parseFloat(yout1[0]);
var nowM = parseFloat(yout1[1]);
var nowD = parseFloat(yout1[2]);
var h = parseFloat(yout2[0]);
var m = parseFloat(yout2[1]);
var s = parseFloat(yout2[2]);
var daysMonth = new Array(31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31);
if(leapyear(nowY))
daysMonth[1] += 1;//闰年,2月加1
s = s + 1;
if (s >= 60)
{
s = 0;
m = m + 1;
if (m >= 60)
{
m = 0;
h = h + 1;
if (h >= 24)
{
h = 0;
nowD += 1;
if(nowD > daysMonth[nowM-1])
{
nowD = 1;
nowM += 1;
if(nowM > 12)
{
nowM = 1;
nowY += 1;
}
}
}
}
}
if (nowM < 10) nowM = "0" + nowM;
if (nowD < 10) nowD = "0" + nowD;
if (h < 10) h = "0" + h;
if (m < 10) m = "0" + m;
if (s < 10) s = "0" + s;
document.getElementById('ServerTime').value = nowY + "-" + nowM + "-" + nowD + " " + h + ":" + m + ":" + s;
var today,hour,second,minute,year,month,date;
var strDate ;
//注意:Javascript中的月要减1,比如现在4月,要写成3
today=new Date(yout1[0],yout1[1]-1,yout1[2],yout2[0],yout2[1],yout2[2]);
var n_day = today.getDay();
switch (n_day)
{
case 0:{
strDate = "星期日"
}break;
case 1:{
strDate = "星期一"
}break;
case 2:{
strDate ="星期二"
}break;
case 3:{
strDate = "星期三"
}break;
case 4:{
strDate = "星期四"
}break;
case 5:{
strDate = "星期五"
}break;
case 6:{
strDate = "星期六"
}break;
case 7:{
strDate = "星期日"
}break;
}
year = today.getFullYear();
month = today.getMonth() + 1;
date = today.getDate();
hour = today.getHours();
minute =today.getMinutes();
second = today.getSeconds();
if(month<10) month="0"+month;
if(date<10) date="0"+date;
if(hour<10) hour="0"+hour;
if(minute<10) minute="0"+minute;
if(second<10) second="0"+second;
document.getElementById('divCurrentUser').value = "当前时间:" + year + "年" + month + "月" + date + "日 " + strDate +" " + hour + ":" + minute + ":" + second; //显示时间
setTimeout("getServerTime()",1000)
}
//判断参数是否闰年
function leapyear(year){
if(!/[^0]\d+/.test(year)){
//通过正则判断年份的合法性
return false;
}
if(0==year)
return true;
if ( ((0==year%4) && !(0==year%100)) || (0==year%400) ){
return true;
}else{
if(year!=0)
return false;
}
}
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